WAP to print all even number between 1 to n using while loop

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C program to print all even numbers between 1 to n using while loop

Write a C program to enter any number from user and print all even numbers between 1 to n using while loop. C program to display even number in a given range using while loop. How to generate even numbers from 1 to n using while loop in C programming.

Example:
Input value of n: 10
Output even numbers between 1 to 10: 2, 4, 6, 8, 10

Also do check this program using for loop - C program to print all even numbers between 1 to n using for loop. 
Required knowledge
Basic C programming, If else, While loop 
Even numbers
Numbers that are exactly divisible by 2 are called as even numbers. Example: 2, 4, 6, 8, 10 are the first 5 even numbers.

Before moving to this program you must know how to check whether a number is even or odd using if else.


Program to print even numbers using if
/**
 * C program to print all even numbers from 1 to n
 */

#include <stdio.h>

int main()
{
    int i, n;
 
    //Reads the upper limit of even number from user
    printf("Print all even numbers till: ");
    scanf("%d", &n);

    printf("All even numbers from 1 to %d are: \n", n);

    /*
     * Starts loop counter from 1, increments by 1 till i<=n
     */
    i=1;
    while(i<=n)
    {
        /* Check even condition before printing */
        if(i%2==0)
        {
            printf("%d\n", i);
        }

        i++;
    }

    return 0;
}

Note: As I already mentioned the above method of generating even numbers is not optimal and takes more time to execute. Hence you must use the below method to generate even numbers.


Program to display even numbers without using if statement
/**
 * C program to display all even numbers from 1 to n using while loop
 */

#include <stdio.h>

int main()
{
    int i, n;
 
    //Reads the upper limit of even number from user
    printf("Print all even numbers till: ");
    scanf("%d", &n);

    printf("All even numbers from 1 to %d are: \n", n);

    i=2; //Since 2 is the first even number
    while(i<=n)
    {
        printf("%d\n", i);

        /*
         * Adding 2 to current even number will give next even number
         */
        i += 2;
    }

    return 0;
}

Output
X=_
Print all even numbers till: 100
All even numbers from 1 to 100:
2
4
6
8
10
12
14
16
18
20
22
24


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