WAP to count total number of notes in given amount
Finding the Number of 500, 100, 50, 20, 10, 5, 2, 1 Rupee Notes in a Given Amount
Here's a fun program in C programming language to find the number of 500, 100, 50, 20, 10, 5, 2, 1 rupee notes in a given amount. It'll surely help cashiers to mange things properly.
# include <stdio.h>
# include <conio.h>
void main()
{
int rs, a, b, c, d,
e, f, g, h ;
clrscr() ;
printf("Enter
the amount in Rupees : ") ;
scanf("%d",
&rs) ;
while(rs >= 500)
{
a = rs / 500 ;
rs = rs % 500;
printf("\nThe
no. of five hundreds are : %d", a) ;
break ;
}
while(rs >= 100)
{
b = rs / 100 ;
rs = rs % 100;
printf("\n\nThe
no. of hundreds are : %d", b) ;
break ;
}
while(rs >= 50)
{
c = rs / 50 ;
rs = rs % 50;
printf("\n\nThe
no. of fifties are : %d", c) ;
break ;
}
while(rs >= 20)
{
d = rs / 20 ;
rs = rs % 20;
printf("\n\nThe
no. of twenties are : %d", d) ;
break ;
}
while(rs >= 10)
{
e = rs / 10 ;
rs = rs % 10;
printf("\n\nThe
no. of tens are : %d", e) ;
break ;
}
while(rs >= 5)
{
f = rs / 5 ;
rs = rs % 5;
printf("\n\nThe
no. of fives are : %d", f) ;
break ;
}
while(rs >= 2)
{
g = rs / 2 ;
rs = rs % 2;
printf("\n\nThe
no. of Twos are : %d", g) ;
break ;
}
while(rs >= 1)
{
h = rs / 1 ;
rs = rs % 1;
printf("\n\nThe
no. of ones are : %d", h) ;
break ;
}
getch() ;
}
Output of above program is
Enter the amount in Rupees : 698
The no. of five
hundreds are : 1
The no. of hundreds
are : 1
The no. of fifties are
: 1
The no. of twenties
are : 2
The no. of fives are :
1
The no. of Twos are :
1
The no. of ones are :
1
Explanation of above program
Above program is pretty straightforward. All it does is that it takes an amount as input and shows how many 500, 100, 50, 10, 5, 2, 1 notes are needed. As this program contains all basics of C programming, lets understand this program by an example.
Remember: When you divide two integer and stores the value in an integer only integer part of the result is stored e.g. 10 / 3 = 3.333 but when you store this result in another integer, it will only hold 3 as its value (to store the exact result use float as data type).
Also in C, % is modulus and is used to calculate remainder so e.g. 5 % 3 will be 2.
Suppose, rs = 698. Now we go step by step .
- First while loop executes as 698 >= 500, so a = 698 / 500 = 1 and rs = rs % 500 = 698 % 500 = 198. The printf() is executed.
- Next while loop executes as 198 >= 100, so a = 198 / 100 = 1 and rs = rs % 100 = 198 % 100 = 98. The printf() is executed.
- Next while loop executes as 98 >= 50, so a = 98 / 50= 1 and rs = rs % 50 = 98 % 50 = 48. The printf() is executed.
- Next while loop executes as 48 >= 20, so a = 48 / 20= 2 and rs = rs % 20 = 48 % 20 = 8. The printf() is executed.
- The next while loop is not executed because 8 < 10.
- Next while loop executes as 8 >= 5, so a = 8 / 5= 1 and rs = rs % 5 = 8 % 5 = 3. The printf() is executed.
- Next while loop executes as 3 >= 2, so a = 3 / 2= 1 and rs = rs % 2 = 3 % 2 = 1. The printf() is executed.
- Next while loop executes as 1 >= 1, so a = 1 / 1= 1 and rs = rs % 1 = 1 % 1 = 0. The printf() is executed.
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